Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Answer:
Answer: D. Q(5, −6) and R(−5, 6)
Step-by-step explanation:
The height of the can for this case is given by:
h = 40 mm
The radius of the can is given by:
r = (1 3/8) * h
Substituting values:
r = (1 3/8) * 40
r = 55 mm
Therefore, the diameter of the can is:
d = 2 * r
d = 2 * 55
d = 110 mm
Answer:
The diameter of the can will be:
d = 110 mm
Answer:
£910
Step-by-step explanation:
let 3x and 7x be the initial amounts in their accounts, then after alterations
Terry has 3x + 220
Faye has 7x - 300
After these changes the amounts are equal, hence
7x - 300 = 3x + 220 ( subtract 3x from both sides )
4x - 300 = 220 ( add 300 to both sides )
4x = 520 ( divide both sides by 4 )
x = 130
Faye initially had 7 × £130 = £910 in her account
