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seropon [69]
3 years ago
14

What is 5 and 1/2 divided by 1/2, please I think the answer is 11 but I need help understanding how we get 11 or the correct ans

wer! :D
Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer:

11

Step-by-step explanation:

Turn 5 and 1/2 into a full fraction by multiplying the denominator (2) and whole number (5). And add that to the number you already have in the numerator (1).

2x5=10

10+1=11

11/2

When dividing fractions, follow the "keep, change, flip" rule:

Keep the dividend (11/2) the same, change the division sign to a multiplication sign, and flip the divisor (1/2). The equation is now

11/2 x 2/1

Cross-simplify the 2's:

11/1 x 1/1

= 11

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What is the value of X ? 4/25 = X/250
Allushta [10]

Answer:

x=40

Step-by-step explanation:

4/25 = X/250

x=(4 . 250) /25

x=40

8 0
4 years ago
Read 2 more answers
A customer placed an order with a bakery for cupcakes. The baker has completed 37.5% of the order 81 cupcakes. How many cupcakes
Paul [167]

Answer:

The total number of cupcakes ordered=216

Step-by-step explanation:

The total number of cupcakes ordered that the baker completed can be expressed as;

C=P×t

where;

C=Total number of completed order of cupcakes

P=percentage of order completed

t=total number of ordered cupcakes

In our case;

C=81

P=37.5%

t=t

replacing in the above expression;

81=37.5%×t

(37.5/100)×t=81

t=81×100/37.5

t=216

The total number of cupcakes ordered=216

3 0
3 years ago
[100 POINTS]!!
Eva8 [605]
1sqmeter=100x100=100000sqcm
in 1sqcm there are 23/100=.23 grass plants
Therefore, there will be .23x100000=2300 grass plants in a sq.meter
5 0
3 years ago
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Compute the differential of surface area for the surface S described by the given parametrization.
AysviL [449]

With S parameterized by

\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle

the surface element \mathrm dS is

\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

We have

\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle

\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle

with cross product

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle

with magnitude

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}

So we have

\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}

8 0
3 years ago
Which of the following is a point on the graph of y-7=3(x-5)
kogti [31]
Answer: (5, 7)

Explanation: The formula for point slope form is,

y2 - y1 = m (x2 - x1)

When you look at the values that have been substituted in, you can see the the x value is 5 and the y value is 7.

When you look at the formula, you can se
7 0
4 years ago
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