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liubo4ka [24]
3 years ago
10

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time

for each unit produced. Use y as the number of units of product 2 produced.
Show the mathematical model when both products are considered simultaneously. Express your answers in terms of x and y.
Mathematics
1 answer:
user100 [1]3 years ago
5 0

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

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\bold{\huge{\orange{\underline{ Solution }}}}

\bold{\underline{ Given :- }}

  • <u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
  • <u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>

\bold{\underline{ To \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>

\bold{\underline{ Let's \: Begin :- }}

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

Cost of 1 share of ABC company = $18.75

<u>Therefore</u><u>, </u>

Cost of 140 shares purchased by Jan in the ABC company

\sf{ = 140 × 18.75 }

\sf{ = 2625\: dollars }

<u>Now</u><u>, </u>

For next 3 days, the value of share declined

\sf{ = (1 + 1.75 + 1.50)dollars }

\sf{ = 4.25 \: dollars }

<u>Therefore</u><u>, </u>

The value of shares after 3 days will be

\bold{ = }{\bold{\frac{2625 - 4.25}{ 140}}}

\bold{ = }{\bold{\frac{ 2620.75}{ 140}}}

\bold{\red{ = 18.75\: dollars}}

Hence, The value of share after 3 days will be $18.75 .

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