Let x be the length of the rectangle, then its width is x-2.
The area of a rectangle is L x W OR x.(x-2). Expand it = x² - 2x = AREA.
Or x² - x = 168
x²-2x-168 = 0. This is a quadratic equation to solve for x:
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
you will find x' =14 and x" = -12 (extraneous value not to be considered), so
x=14
Answer:
The Cardboard dimensions are 13cm in length and 12cm in breadth
Step-by-step explanation:
We can use Pythagoras Theorem to find the length the Cardboard (a²+b²=c²). Let A be 5 and B be 12, we find that C is equivalent to 13. The height is 12, thus the breadth of the Cardboard is also 12. Hope this helps :)
To start you would count 140 miles and 90 miles and add that together because they are at least that far apart because they are in different directions with the measurement starting at the airport. So you have 230 miles. Then you would know that plan A is 3 miles up and plane B is only 2 miles up, so there's one more mile between them. So you can add that and say 231 miles.
Answer:
p = 1.2
Step-by-step explanation:
The given equation is :
–4.6p – 6.3p + 3.9 = –9.18
Combining the like terms,
–4.6p – 6.3p = -9.18 - 3.9
−10.9p = −13.08
⇒ 
Hence, the value of p is 1.2
hi
technique is to decompose both part of the fraction ( in prime numbers if possible )
8 * 5/6 = 2*4*5 / 3*2 = 20/3
