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Veronika [31]
3 years ago
14

What is the value of the t score for a 99% confidence interval if we take a sample of size 22?

Mathematics
1 answer:
Elanso [62]3 years ago
5 0

Answer: 2.831

Step-by-step explanation:

As per given , we have

sample size : n= 22

Degree of freedom = n-1 = 22-1=21

Significance level for 99% confidence interval = \dfrac{1-0.99}{2}=0.005

Using student's t-value table, we have

t_{0.005,\ 21}=2.831

Hence, the  t score for a 99% confidence interval if we take a sample of size 22= 2.831

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Step-by-step explanation:

The correct answer doesn't seem to be listed...

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