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2 years ago

The sum of two numbers is 21.The second is 6 times the first number .work out the two numbers

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

$n-first\ number\\\text{the second number is 6 times the first number}\\6n-second\ number\\\\\text{the sum is 21:}\\\\n+6n=21\\7n=21\qquad\text{divide both sides by 7}\\\boxed{n=3}\\\\6n=6(3)\\\boxed{6n=18}$

Nimfa-mama [501]2 years ago

4 0

Answer:

Sum of the two numbers is 21 and Second number is six times the first number

x+6x = 21

7x = 21

x = 21/7

x = 3

substitute x value in 6x to find second number,

= 6x

= 6*3

= 18

Therefore first number is 3 and second number is 18

Step-by-step explanation:

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2 years ago

-14(3a+6)=12(6-4a)+12 and steps please

Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

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