Question

The sum of two numbers is 21.The second is 6 times the first number .work out the two numbers

Answer 1

Answer:

3 and 18

Step-by-step explanation:

$n-first\ number\\\text{the second number is 6 times the first number}\\6n-second\ number\\\\\text{the sum is 21:}\\\\n+6n=21\\7n=21\qquad\text{divide both sides by 7}\\\boxed{n=3}\\\\6n=6(3)\\\boxed{6n=18}$

Answer 2

Answer:

Sum of the two numbers is 21 and Second number is six times the first number

x+6x = 21

7x = 21

x = 21/7

x = 3

substitute x value in 6x to find second number,

 = 6x

 = 6*3

 = 18

Therefore first number is 3 and second number is 18

Step-by-step explanation: