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aleksklad [387]

3 years ago

8

I’ll 40 points for these answers, thank you

2 answers:

attashe74 [19]3 years ago

3 0

1. 24%
2. 13%
3. 60%

1. Since 6/25 is .24, 24% of the class was absent
2. He spent 3 hours in total.. Divide is by 24 because there are 24 hours in a day. 3/24 is 0.125 for 13% of the day
3. He ran 3 of the 5 miles, so 3/5 = 0.6.. meaning 60%. The time doesn’t matter

Leno4ka [110]3 years ago

3 0

Answer:

1.) 24%

2.) 12.5%

3.) 60%

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Answer:

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Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first term and r be the common ratio.

The $n^{th}$ term of a geometric sequence is given by:

$a_n = ar^{n-1}$

There are 16 teams remaining in round 4 and 4 teams in round 6.

Thus, we can write:

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4}=\dfrac{ar^3}{ar^5}\\\\4=\dfrac{1}{r^2}\\r^2=\dfrac{1}{4}\\\\r = \dfrac{1}{2}$

Putting value of r in he equation we get:

$16=a(\dfrac{1}{2})^2\\\\a = 16\times 2^3\\a = 128$

Thus, the geometric sequence can be written as:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

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Answer:

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