If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]? a)29.5 b)30 c)43 d)120

1 answer:

7 0

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
f(x)= x^3-x \qquad 
\begin{cases}
x_1=1\\
x_2=5
\end{cases}\implies \cfrac{f(5)-f(1)}{5-1}
\\\\\\
\cfrac{[5^3-5]~-~[1^3-1]}{4}\implies \cfrac{125-5~~-~~0}{4}\implies \cfrac{120}{4}\implies 30$

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Which expression represents the sixth term in the binomial expansion of (5y+3)^10

olga nikolaevna [1]

$\bf \textit{the coefficient and values of an expanded term}\\\\
(5y-3)^{10} \qquad \qquad 
\begin{array}{llll}
expansion\\
for\\
6^{th}~term
\end{array} \quad 
\begin{cases}
\stackrel{term}{k}=0..10\\
\stackrel{exponent}{10}\\
-----\\
k=\stackrel{6^{th}~term}{5}\\
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\end{cases}$

$\bf \stackrel{coefficient}{\left(\frac{n!}{k!(n-k)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( a^{n-k} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( b^k \right)}$

$\bf \stackrel{coefficient}{\left(\frac{10!}{5!(10-5)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( (5y)^{10-5} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( (-3)^5 \right)}
\\\\\\
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\\\\\\
-191362500y^5$

8 0

3 years ago

Name<br> Add and Subtract Integers<br> Solve.<br> 1.-2+9

Rudiy27

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enyata [817]

Answer:

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