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3 years ago

First right answer gets brain

Mathematics

2 answers:

pantera1 [17]3 years ago

5 0

I believe the answer is going to be B

kotegsom [21]3 years ago

4 0

Line graph of course.

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If f(x) is a function and f(1) = 5, then which of the following could not be true?

vodomira [7]

A. you are given that f(1)=5 therefore f(1) cannot also equal 1 unless it is a different equation.

5 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

What is 700,000,000,000 written in scientific notation?

Cerrena [4.2K]

The answer is 7*10^11

6 0

3 years ago

Two studies were done on the same set of data, where study I was a one-sided test and study II was a two-sided test. The p-value

mixer [17]

Answer:

$0.060$

Step-by-step explanation:

In a two tailed test the probability of occurrence is the total area under the critical range of values on both the sides of the curve (negative side and positive side)

Thus, the probability values for a two tailed test as compared to a one tailed test is given by the under given relation -

$p-value = P(Z< -\frac{\alpha }{2} )+P(Z >\frac{\alpha}{2})$ \

Here $P\frac{\alpha}{2} = 0.030$

Substituting the given value in above equation, we get -

probability values for a two tailed test

= $0.030 + 0.030\\= 0.060$

4 0

2 years ago

Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Wr

Greeley [361]

The probability of one head and one tail is 2/3.

Step-by-step explanation:

The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities

Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

8 0

3 years ago