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777dan777 [17]
3 years ago
8

PLEASE HELP I NEED TO FINISH THIS

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:ujjj

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When twotwo basketball players are about to have a​ free-throw competition, they often draw names out of a hat to randomly selec
erica [24]
There are 2! = 2 ways to arrange the names of two basketball players in a hat.

Since, the are going to throw alphabetically, there is 1 way for the names to be arranged alphabetically.

Therefore, <span>the probability that they shoot free throws in alphabetical​ order is \frac{1}{2} = 0.5</span>
6 0
3 years ago
Simplify 9 + 6k +3 +212 +3 +7​
melisa1 [442]

Answer:

6k+234

Step-by-Step Explanation:

Add 9, 3, 212, 3, and 7. You get 234. You can't change 6k because the variable, so you end up with 6k+234.

8 0
3 years ago
Read 2 more answers
Can you guys name the property please.
Setler [38]

Answer:

I think A. Reflexive Property but if I am wrong, I am so sorry

Step-by-step explanation:

because 6 + 1 is is not subtracting or multiplying

Hope this helps

3 0
3 years ago
Gabrielle uses 7.6 pints of blue paint and white paint to paint her bedroom walls. 1 4 of this amount is blue paint, and the res
zysi [14]

Answer:

1.9

Step-by-step explanation:

Gabrielle uses 7.6 pints of blue and white paint to paint her bedroom

1/4 of the paint is blue paint

Therefore the amount of white paint she used to paint her bedroom can he calculated as follows

= 1/4

= 0.25×100

= 25%

25/100×7.6

= 2.5 × 7.6

= 1.9

Hence 1.9 pints of white paint was used to paint the room

6 0
3 years ago
A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested
Xelga [282]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1

4 0
3 years ago
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