Answer:
a) 0.11%
b) 55.99%
c) 0.25%
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 54.3 pounds and a standard deviation of 14.5 pounds.
This means that 
1. What percentage of Americans' annual salad and cooking oil consumption is less than 10 pounds?
The proportion is the pvalue of Z when X = 10. So



has a pvalue of 0.0011
0.0011*100% = 0.11%.
2. What percentage of Americans' annual salad and cooking oil consumption is between 35 and 60?
The proportion is the value of Z when X = 60 subtracted by the pvalue of Z when X = 35.
X = 60



has a pvalue of 0.6517
X = 35



has a pvalue of 0.0918
0.6517 - 0.0918 = 0.5599
0.5599*100% = 55.99%
3. What percentage of Americans' annual salad and cooking oil consumption is more than 95 pounds?
The proportion is 1 subtracted by the pvalue of Z when X = 95.



has a pvalue of 0.9975
1 - 0.9975 = 0.0025
0.0025*100% = 0.25%
Answer:
9 and 11
2x+9x=(2+<em>9</em>)x=11x
<u>Answer:</u>
19.5 x 29.25 inches
<u>Step-by-step explanation:</u>
We are given that the top of the table, which we are to build in our factory must of the the dimension 50 cm x 75 cm.
Also, out machine is calibrated in inches. So to find the size of the table in the inches, we need to multiply the given dimensions of the table top with the scale (1 cm = 0.39 inches)
50 cm ---> 50 x 0.39 = 19.5 inches
75 cm ---> 78 x 0.39 = 29.25 inches
Therefore, the dimensions of the table in inches are 19.5 x 29.25 inches.
Each runners time would be an average of 18.1
72.4/4=18.1