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Bas_tet [7]
3 years ago
6

Which is larger 80% or 1/8

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
4 0

So 1/8 as a percentage is 12.5%.

80% is greater than 12/5%.

So your answer would be 80%.

ZanzabumX [31]3 years ago
4 0
Definitely 80% because it is a bigger number
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≈1.7308
100*1.7308=173.08
The unknown number is approximately 173.08.

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Simplify expression <br><br><br>A.
MA_775_DIABLO [31]
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Question 20 please make (x) the subject of the formula
Masja [62]

Answer:

The answer is

\frac{ {x}^{2}  - n}{m}  =  { (\frac{ {a}^{2} }{b}) }^{a}  \\  {x}^{2}  - n =  m{( \frac{ {a}^{2} }{b} })^{a} \\  {x}^{2}   = m {( \frac{ {a}^{2} }{b} )}^{a}  + n \\ x =  \sqrt{m {( \frac{ {a}^{2} }{b}) }^{4}  - n}

Step-by-step explanation:

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3 0
3 years ago
Will give brainliest plz help
Dominik [7]

Answer:

\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

Step-by-step explanation:

Given:

Center of the ellipse is, (h,k)=(-4,-3)

Minor axis length is, 2b=6

A vertex of the ellipse is at (1, -3)

Now, distance between the center and the vertex is half of the length of the major axis.

Using distance formula for (-4, -3) and (1, -3), we get:

a=\sqrt{(1+4)^2+(-3+3)^2}=5

Therefore, the value of half of major axis is, a=5. Also,

2b=6\\b=\frac{6}{2}=3

Now, equation of an ellipse with center (h,k) is given as:

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

Plug in h=-4,k=-3,a=5,b=3 and determine the equation.

\frac{(x-(-4))^2}{5^2}+\frac{(y-(-3))^2}{3^2}=1\\\\\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

Therefore, the equation of the ellipse is:

\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

6 0
3 years ago
How to slove 4x+15=-4x+10
insens350 [35]
The 4x's get eliminated because they are opposite. So just add 10+15= 25
6 0
3 years ago
Read 2 more answers
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