4 times the difference between Evan's age "x," and 44 is 64. Write an equation to express Evan's age.

Ralph and Waldo start in towns that are 70 miles apart and travel in opposite directions for 4 hours.

Lina20 [59]

Answer:

Step-by-step explanation:

Let Waldo's speed = W

Let Ralph's speed = W + 15

A

Waldo's distance = speed * Time

Time = 4 hours.

Speed = w

distance = 4 * w

B

Ralph's speed is W + 15. It's not clear if you need a number. We'll get around to that later.

C

Ralph traveled 4*(W + 15)

D

4w + 70 + 4(W + 15) = d

You really can't get a definite answer to these questions. Even if you knew whether they were heading away from each other or towards each other it wouldn't help.

6 0

2 years ago

. A piece of wire is 11 1/4 yards long. It is cut into 9 equal pieces. What is the length of each piece of the wire? *

laila [671]

djdhdhusidhdushdhd

Carryonlearning <3

The number of subsets of a set is 256, and the number of subsets of a set is 128. If | ∪ | = 2 × | ∩ |, then what is the value of | ∩ |? and what will be the number of subsets of the set ∩ ?

3 0

2 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

2 years ago

Explain a real life situation where you may use trig ratios to find measure in right triangles.

OLEGan [10]

One example is if you wanted to measure the height of a tall building. You'll need to measure the distance from where you're standing to the base of the building. You'll also need the angle of elevation. To get the angle of elevation, start by looking completely horizontal, then tilt upward until your eyeline reaches the top of the building. Once you have those two things (the side and angle) you can use the tangent ratio to find the height. This is because

tan(angle) = opposite/adjacent

where in this case
angle = angle of elevation
opposite = height of building
adjacent = distance from your position to the base of the building

It takes a bit of algebra, but the opposite side can be solved for. You'll most likely need a calculator to compute the tangent ratio.

5 0

3 years ago

Solve for n: 3n + 2 – n = -4

Sav [38]

The value of x is -3, or x= -3

6 0

2 years ago