Answer:
Explanation:
Hello.
In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:
The distance is clearly 1743 km and the time is:
Thus, the velocity turns out:
Which is a typical velocity for a plane to allow it be stable when flying.
Best regards.
Answer:
0.2
Explanation:
The given parameters are;
The acceleration of the train, a = 0.2·g
The mass of the person standing on the train = m
Let μ represent the coefficient of static friction, we have;
The force acting on the person, F = m × a = m × 0.2·g
The force of friction acting between the feet and the floor, = m·g·μ
For the person not to slide we have;
The force acting on the person = The force of friction acting between the feet and the floor
F =
∴ m × 0.2·g = m·g·μ
From which we get;
0.2 = μ
The coefficient of static friction that must exist between the feet and the floor if the person is not to slide, μ = 0.2.