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Alika [10]
3 years ago
9

What is the average acceleration of the object represented in the graph above over the eight seconds? 0.5 cm/s2 1.0 cm/s2 1.5 cm

/s2 2.0 cm/s2
Physics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

Draw tangents to the graph at 1.0 s and 5.0 s. 0. 1. 2. 3. 4. 5. 6. 0 ... When the velocity component is negative, the extra displacement during ... 2 - 3 min. constant acceleration component until the car stops. ..... ii). The gravitational force and the drag force are doing work on the object. .... N) × (0.5 m) = 5 × 10. 2.

Explanation:

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An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D
Inga [223]
A high quality insecticide applied all along the axis and the surrounding area can protect against a recurrence for a substantial period of time.
5 0
3 years ago
A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
prisoha [69]

0J

Explanation:

A wall that is acted upon by a force of 20N does not move suggests that no work has been done on the wall.

Work done is the force applied to move in the direction of the applied force.

   Work done = force x distance.

Since the distance is 0, the work done on the body too is zero.

Work is only done when forces moves a body through a given distance.

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

5 0
3 years ago
A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , wher
zhuklara [117]

Answer:

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

x(t) = Acos(\omega t - \phi)

where A is the amplitude, \omega = 2\pi f is the angular frequency and \phi is the initial phase.

Since our body has an equation of  x = 5cos(π t + π/3) we can equate \omega = \pi and solve for frequency f

2\pi f = \pi

f = 1/2 Hz

7 0
3 years ago
Read 2 more answers
A race car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of
OLEGan [10]

Answer:

c)F_{net} = 0.640 kN

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

F_{net} = ma

here we know

m = 80 kg

for circular motion acceleration is given as

a_c = \frac{v^2}{R}

a_c = \frac{40^2}{200} = 8 m/s^2

now we have

F_{net} = 80 \times 8

F_{net} = 640 N

F_{net} = 0.640 kN

7 0
3 years ago
A type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Romashka [77]

Answer:

Air resistance

Answer B is correct

Explanation:

The friction that occurs when air pushes against a moving object causing it to negatively accelerate is called as air resistance.

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0
3 years ago
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