A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi
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Answer:
a) F = (137.4 i ^ + 185 j ^) N
b) F = 230.2 N , θ = 53.5º
Explanation:
In this exercise we ask to find the net force, for which we will define a coordinate system fix the donkey and use trigonometry to decompose the forces
Jack F₁ₓ = 63.9 N
Jill F₂ = 79.1 N with direction 45º to the left
cos (180 -45) = F₂ₓ / F₂
sin 135 = / F₂
F₂ₓ = F₂ cos 135
F_{2y} = F₂ sin 135
F₂ₓ = 79.1 cos 135 = -55.9 N
F_{2y} = 79.1 sin 135 = 55.9 N
Jane F₃ = 183 N direction 45th to the right
cos 45 = F₃ₓ / F3
sin 45 = F_{3y} / F3
F₃ₓ = F₃ cos 45 = 183 cos 45
F_{₃y} = F₃ sin 45 = 183 sin 45
F₃ₓ = 129.4 N
F_{3y} = 129.4 N
we add each component of the force
Fₓ = F₁ₓ + F₂ₓ + F₃ₓ
Fₓ = 63.9 + (-55.9) + 129.4
Fₓ = 137.4 N
F_{y} = F_{2y} + F_{3y}
F_{2y} = 55.9 + 129.4
F_{2y} = 185.3 N
we can give the result of the forms
a) F = (137.4 i ^ + 185 j ^) N
b) in the form of module and angle
F = RA (Fₓ² + F_{y}²)
F = Ra (137² + 185²)
F = 230.2 N
tan θ = F_{y} / Fₓ
θ = tan⁻¹ F_{y} / Fₓ
θ = tan⁻¹ (185/137)
θ = 53.5º
Answer:
1) Ex(P) = -8.34602 N/C
2) = -5.23850174216 N/C
3) Question (3) is a similar question to (1)
4) = -5.23850174216 N/C
5) ≈ 1.041466 C/m²
6) σₐ ≈ 2.2330413 C/m²
Explanation:
The given parameter of the point charge located at the center of a conducting shell
The charge of the point charge, q₁ = -8.9 μC
The inner radius of the shell, a = 2.8 cm
The outer radius of the shell, b = 4.1 cm
The charge of the conducting shell, q₂ = 2.2 μC
Therefore, we have;
1) The point P(8.5, 0)
By plugging in the values, we have;
For
R₁ < R₂ < r, for the electric field at the point, 'P', we have;
Ex(P) = -8.34602 N/C
2) For the point given with coordinates (8.5, 0), the distance of the y-component of point from the center = 0
The y-component of the electric field = 0 N/C
4) For r = 1.4 cm, along the y-axis we have;
R₁ < r < R₂
Therefore, we have;
Substituting the values, we get;
= -5.23850174216 N/C
5) The charge density, , is given as follows;
6) Similarly, we have;