However, during prophase. I homologous chromosomes pair up and become attached to one another. At this time, crossing over<span> moves sections of DNA between homologous chromosomes and allows for </span>independent assortment<span>. particular chromosome when </span>crossing over<span> does not occur. that is the answer</span>
The answer using the formula f=1/T is f=1/5 which is 0.2hertz
Answer:
c.) increased glucose uptake to the liver from blood
Explanation:
During stressful conditions such as facing a mugger, the sympathetic system of the autonomic nervous system is activated. There is a release of stress hormones from the adrenal glands to produce the flight or fight response. One of the physiological events occurring during these conditions is the breakdown of glycogen into glucose in liver cells and the release of glucose into the blood. The release of glucose by the liver increases blood glucose levels. This is done to ensure glucose availability as fuel. There is no uptake of glucose from the liver cells under such emergency conditions.
The rotator cuff tendons enclose the shoulder joint on all sides except on the bottom side, which partly explains the nature of most shoulder dislocations.
Rotator cuffs are a type of tendons that surround the shoulder and help in keeping the upper arm in its location and also attached to the shoulder joint. The upper arm is connected at the socket of the shoulder.
Shoulder dislocation is the injury where the upper arm is dislocated from its exact location of the socket of shoulder joint. This can also cause damage to the ligaments. Shoulder dislocation can be of three types: anterior, posterior and inferior.
To know more about rotator cuffs, here
brainly.com/question/9486780
#SPJ4
Answer:
8.800s
Explanation:
When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.
First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation
T = 2π×√(Lo/g)..... (1)
Let's make Lo the subject of the formulae
Lo = gTo^2/4π^2 ..... (2)
Let's put our values into equation (2) to get Lo
Lo = gTo^2/4π^2
= (9.8m/s^2)(8.90s)^2
------------------------------
4π^2
= 19.663m
Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be
L = Lo - (0.44m)
= 19.663m - 0.44m
= 19.223m
Now let use the value of L into equation (1) to get the period T after raising
T = 2π×√(L/g)
= 2π×√(19.223m/9.8m/s^2)
= 8.800s
