Can you please find the missing side these are similar figures.

At a store, 4 pairs of pants cost $90.00 and 4 pairs of jeans cost $78.00. How much would it cost to buy 3 pairs of pants and 5

liq [111]

$67.50 for three pairs of pants. $97.50 for five pairs of jeans. For all of these the price would be $165.00

5 0

4 years ago

During a radio contest, $50 is added to the prize money each time a caller answers the contest question incorrectly. the first c

omeli [17]

Answer:

50x+100=y
y=550

Step-by-step explanation:

Since the first caller can win $100, you add 100 onto the end. After you add 50 for every person who answered incorrectly. X being amount tried/answered incorrectly, and Y being the amount you can win at that given time

6 0

2 years ago

Can someone give the answer for the number pattern show your work, I am struggling. Please!

Anna [14]

To solve this you have to take the numbers and subtract them and that will give you the pattern.
Ex. For #9 do 26-19 then to check and see if that helps the pattern do 36-26
Hope this helps:)

5 0

4 years ago

Read 2 more answers

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0

3 years ago

8+[5×6]= i need answer asap pls

Karo-lina-s [1.5K]

Answer:

38

Step-by-step explanation:

Follow orders of operations.

Slove the expression in the parenthesis or brackets whatever, same thing.

5*6=30

Now add

30+8=38

5 0

3 years ago

Read 2 more answers