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tangare [24]
3 years ago
14

What is the better estimate for the mass of a textbook, 1 gram or 1 kilogram

Mathematics
2 answers:
frez [133]3 years ago
8 0
I kilogram, 1 gram would be a speck of dust 
Tems11 [23]3 years ago
3 0
1 kilogram<span>,because one </span>gram<span> would be about a piece of paper.</span>
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Convert 50 degrees into radians (NEED ASAP)
MA_775_DIABLO [31]

Answer:

0.872665

Step-by-step explanation:

6 0
3 years ago
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Describe at least two similarities between constructing a perpendicular line through a point on a line and constructing a perpen
Sophie [7]

Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;

  • 1. Arcs are drawn to cross the given line twice on either side relative to the point
  • 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line

Description:

1. One of the first steps is to place the compass on the point and from

point, draw arcs to intersect or cross the given line at two points.

2. The compass is placed at each of the intersection point in step 1 and

(opened a little wider when constructing from a point on the line) arcs are

drawn on one (the other side of the point off the line) side of the line with

the same opening (radius) of the compass to intersect each other.

3. From the point of intersection of the arcs in step 2, a line is drawn with a

straight edge passing through the given point.

Learn more about perpendicular lines here:

brainly.com/question/11505244

8 0
2 years ago
This table is proportional. What is the constant of proportionality?<br> k=
swat32

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
Solve the system of equations 2x+4y+3z=6 5x+8y+6z=4
MaRussiya [10]

Answer:Solution :

{x,y,z} = {-8,52/7,-18/7}  

 

System of Linear Equations entered :

  [1]    2x + 4y + 3z = 6

  [2]    5x + 8y + 6z = 4

  [3]    4x + 5y + 2z = 0

Solve by Substitution :

// Solve equation [3] for the variable  z  

 

 [3]    2z = -4x - 5y  

 [3]    z = -2x - 5y/2  

// Plug this in for variable  z  in equation [1]

  [1]    2x + 4y + 3•(-2x-5y/2) = 6

  [1]    -4x - 7y/2 = 6

  [1]    -8x - 7y = 12

// Plug this in for variable  z  in equation [2]

  [2]    5x + 8y + 6•(-2x-5y/2) = 4

  [2]    -7x - 7y = 4

// Solve equation [2] for the variable  y  

 

 [2]    7y = -7x - 4

 [2]    y = -x - 4/7

// Plug this in for variable  y  in equation [1]

  [1]    -8x - 7•(-x -4/7) = 12

  [1]    -x = 8

// Solve equation [1] for the variable  x  

  [1]    x = - 8  

// By now we know this much :

   x = -8

   y = -x-4/7

   z = -2x-5y/2

// Use the  x  value to solve for  y  

   y = -(-8)-4/7 = 52/7  

// Use the  x  and  y  values to solve for  z  

 z = -2(-8)-(5/2)(52/7) = -18/7  

Solution :

{x,y,z} = {-8,52/7,-18/7}  

Step-by-step explanation:

4 0
3 years ago
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