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Amiraneli [1.4K]
3 years ago
7

Find an equation equivalent to r = 10 sin theta rectangular coordinates.

Mathematics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer:

x^2+y^2=10y

Step-by-step explanation:

d on edg

bazaltina [42]3 years ago
4 0

We have been an equation in polar coordinates r=10\text{sin}(\theta). We are asked to write our equation in rectangular coordinates.  

We know that the equation r=2b\text{sin}(\theta) is equation of a circle with a radius |b| and center at (0,b).

Let us find the value of b.

2b\text{sin}(\theta)=10\text{sin}(\theta)

\frac{2b\text{sin}(\theta)}{2\text{sin}(\theta)}=\frac{10\text{sin}(\theta)}{2\text{sin}(\theta)}

b=5

We know that equation of a circle in rectangular coordinates is (x-h)^2+(y-k)^2=r^2

Since b=5, so radius is 5 and center is at point (0,5).

(x-0)^2+(y-5)^2=5^2

x^2+(y-5)^2=25

Therefore, our required equation would be x^2+(y-5)^2=25.

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Find the value of 7v-6 given that -8v-9=7 Simplify your answer as much as possible 7v-6=
evablogger [386]

Answer:

-20

Step-by-step explanation:

-8v-9=7

Add 9 to each side

-8v-9+9=7+9

-8v = 16

Divide by -8

-8v /-8 = 16/-8

v = -2

Now find

7v -6

7(-2) -6

-14 -6

-20

4 0
3 years ago
Read 2 more answers
Use the distributive property to find an expression that is equivalent to <br> 2x(x + 7)-(3x +1)
zaharov [31]

Given expression:

     2x(x + 7)-(3x +1);

To distribute implies to spread a process equally in an expression. Often times, the distributive property is used for expressions inside parentheses;

  2x(x + 7)-(3x +1)  

  Distribute 2x over the first parentheses;

   the negative sign distributes over the second part

    = (2x² + 14x)  - 3x -1

    = 2x² + 14x -3x -1

    Add like terms;

    = 2x² + 11x -1

This expression  2x² + 11x -1 is equal to the given one

7 0
3 years ago
CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0
3 years ago
Find the measure of c. A. 40 B. 70 C. 90 D. 50
Juliette [100K]

Answer:

D. 50

Step-by-step explanation:

a = 90° (angle subtended in semicircle)

a + c + 40° = 180° (by angle sum postulate of a triangle)

90° + c + 40° = 180°

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c = 180° - 130°

c = 50°

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3 years ago
Which of the following is an example of a discrete variable ?
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C.The number of eggs in a cartoon I'm pretty sure
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