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elena-s [515]
3 years ago
8

They who answer first, brainliest is thy prize

Mathematics
2 answers:
konstantin123 [22]3 years ago
7 0

Answer:

Remaineder = -2x+5

quotient = 3x+3

Kamila [148]3 years ago
7 0

Answer:

Quotient: 3x+3

remainder: -2x+5

Step-by-step explanation:

Use polynomial long division

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Dimas [21]
For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.
5 0
3 years ago
Find the area of the triangle with the given base and height.<br> b = 3 m and h = 10 1/2 m
svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is 10 \frac{1}{2} m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

  • Given, base = 3m, height = 10 \frac{1}{2}m
  • We know,

\sf \: area \:  \:  of \:  \: a \:  \: triangle =  \frac{1}{2}  \times base \:  \times height

  • Therefore, the area of the triangle

\sf =  (\frac{1}{2}  \times 3 \times 10 \frac{1}{2} ) {m}^{2}  \\ \sf  = ( \frac{1}{2}  \times 3 \times  \frac{21}{2} ) {m}^{2}  \\  = \sf  \frac{63}{4}  {m}^{2}  \\  =   \sf 15\frac{3}{4}  {m}^{2}

<u>Answer</u><u>:</u>

The area of the triangle is \sf \: 15 \frac{3}{4}  {m}^{2}

Hope you could understand.

If you have any query, feel free to ask.

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2 years ago
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If you are given the opposite side and hypotenuse, which trig function should you use?
Karo-lina-s [1.5K]

Answer:

sin

Step-by-step explanation:

sin is opp/hyp

7 0
3 years ago
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The radius of a cylindrical gift box is (2x+3) in. The height of the gift box is twice the radius. What is the surface area of t
inessss [21]
SA=2pir^2+2hpir=2pir(r+h)
h=2r=2(2x+3)=4x+6

SA=2pi(2x+3)(2x+3+4x+6)
SA=(4x+6)(pi)(6x+9)
SA=24πx²+27πx+54π
3 0
3 years ago
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