Answer: the answer is the first one
Step-by-step explanation:
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
x = 17 and y = 8
Step-by-step explanation:
Since (6x + 3) and (8x - 31) are alternate interior angles, they are congruent.
Therefore, you can set them equal to each other and solve for x.
8x - 31 = 6x + 3
Combine like terms
2x = 34
Divide both sides by two
x = 17
Since (5y + 35) and (6x + 3) are consecutive interior angles, they add up to 180. Plug in 17 for x.
(5y + 35) + (6(17) + 3) = 180
Add like terms
5y + 140 = 180
5y = 40
y = 8
