To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
Answer: 4ab^2 +20b - 3 -3a
Combine like terms.
Combine ab, b, a terms for #1
Combine x^3, x^2, x terms for #2
Answer:
<h2>
65%</h2>
Step-by-step explanation:
<h3>
Given: Full capacity= 200000 litres
</h3><h3>
</h3><h3>
Amount of fuel used during flight= 130000 litres
</h3><h3>
</h3><h3>
Now, finding percentage of fuel used on the flight.
</h3><h3>
</h3><h3>
∴ Percentage of fuel used= </h3><h3>
</h3><h3>
Solving it, we will get </h3><h3>
</h3><h3>
∴ 65% of fuel capacity been used in this flight.</h3>
So,
30%=0.3
36x0.3=10.8
It is $10.80 off
There is a 1/12 chance that 6 will and two times if <span>two 6 sided dice are rolled.</span>
