Answer:
$16,150
Step-by-step explanation:
hope this helps with the work
Answer: The answer is (d) ⇒ cscx = √3
Step-by-step explanation:
∵ sinx + (cotx)(cosx) = √3
∵ sinx + (cosx/sinx)(cosx) = √3
∴ sinx + cos²x/sinx = √3
∵ cos²x = 1 - sin²x
∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M
∴ (sin²x + 1 - sin²x)/sinx = √3
∴ 1/sinx = √3
∵ 1/sinx = cscx
∴ cscx = √3
~Hello There!~
Product means they multiply to make 6
Think of numbers that multiply to make six:
1 x 6
6 x 1
3 x 2
2 x 3
The largest out of those is clearly 6 x 1 which makes 61
Hope This Helps You!
Good Luck :)
Have A Great Day ^_^
- Hannah ❤
The roots of the entire <em>polynomic</em> expression, that is, the product of p(x) = x^2 + 8x + 12 and q(x) = x^3 + 5x^2 - 6x, are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6.
<h3>How to solve a product of two polynomials </h3>
A value of <em>x</em> is said to be a root of the polynomial if and only if <em>r(x) =</em> 0. Let be <em>r(x) = p(x) · q(x)</em>, then we need to find the roots both for <em>p(x)</em> and <em>q(x)</em> by factoring each polynomial, the factoring is based on algebraic properties:
<em>r(x) =</em> (x + 6) · (x + 2) · x · (x² + 5 · x - 6)
<em>r(x) =</em> (x + 6) · (x + 2) · x · (x + 3) · (x + 2)
r(x) = x · (x + 2)² · (x + 3) · (x + 6)
By direct inspection, we conclude that the roots of the entire <em>polynomic</em> expression are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6.
To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910