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3 years ago

Plz help will rank Brainliest!!!!!!!

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

Answer:

4 Units

Step-by-step explanation:

Just count the squares from X to Y or You can do just mental math

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CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM

Klio2033 [76]

Answer:

V ≈ 2011 cm³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = area of base × perpendicular height

V = πr²h ( r is the radius and h the height )

Here r = 8 and h = 10, thus

V = π × 8² × 10

= π × 64 × 10 = 640π ≈ 2011 cm³ ( to nearest whole number )

3 0

2 years ago

In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0

2 years ago

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Help me with this plsss I’ll give brainlist to u

Arturiano [62]

Answer:

7 sticks

Step-by-step explanation:

4 0

2 years ago

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Mrs. chin paid a 20 percent tip on the bill for lunch.if the tip amount was $2.75, what was the bill for lunch before the tip wa

bija089 [108]

The original bill for the lunch was $13.75

8 0

3 years ago

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Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

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5 0

3 years ago