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3 years ago

Solve the Inequality.

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

16(1/4x-1/2)>24-2x

Use the distributive property on the left side:

4x -8 > 24-2x

Add 2x to each side:

6x -8 > 24

Add 8 to each side:

6x >32

Divide both sides by 6:

x > 32/6 reduces to 16/3

Not sure if there is a typo in any of your answers, but I do not see the correct answer listed.

MA_775_DIABLO [31]3 years ago

8 0

Answer:

x>16\3

Step-by-step explanation:

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State all integer values of x in the interval (-3, 3] that satisfy the following

Galina-37 [17]

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.

We have given

-3x+4 > 9

Required values of x.

State the values of x within -3 and 3.

subtract 4 from both sides,

-3x+4-4>9-4

<h3>What is the meaning of like terms?</h3>

like terms are terms that have the same variables and powers. The coefficients do not need to match.

Collect Like Terms

-3x > 5

(-3x)(-1) < 5(-1)

3x < -5

Divide both sides by 3

3x/3 < -5/3

x < -5/3

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.

To learn more about the interval visit:

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3 0

2 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$