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lesya [120]
3 years ago
9

The table below shows the typical hours worked by employees at a company. A salaried employee makes $67,000 per year. Hourly emp

loyees get paid $25 per hour, but get $37.50 per hour for each hour over 40 hours. Sun. Mon. Tues. Wed. Thurs. Fri. Sat. 0 10 8 8 7 6.5 4.5 Which of the payment options would you recommend to a new employee?
a. Either one. Hourly and salaried employees earn the same amount per week.
b. Hourly pay. Hourly employees make more per week than salaried employees. c. Salaried pay. Salaried employees make more per week than hourly employees.
d. There is not enough information given to compare weekly earnings
Mathematics
2 answers:
nadezda [96]3 years ago
7 0
First, we must calculate the weekly pay of an employee that is paid a fixed amount. Given that there are 52 weeks in a year, the weekly pay for a regularly paid employee is: 67,000 / 52 = $1,288.46 Now, we calculate the number of hours an employee that is paid hourly works per week: 0 + 10 + 8 + 8 + 7 + 6.5 + 4.5 = 44 So this employee is paid: 25 x 40 + 37.5 x 4 = $1,150 Therefore, it is recommended that a new employee goes for the salaried pay since the weekly earnings are greater in this option. The answer is C<span>.</span>
posledela3 years ago
7 0
The answer is C. Salaries pay. Salaried employees make more per week than hourly employees.
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Please answer this correctly
Over [174]

Answer:

54 9/10

Step-by-step explanation:

The perimeter is the sum of all the sides

13 1/4 + 12 1/5 + 18 1/4 + 11 1/5

Add up the whole numbers

13+12+18+11 = 54

1/4+1/5+1/4+1/5

2/4+2/5

1/2+2/5

Get a common denominator

1/2*5/5 + 2/5*2/2

5/10 +  4/10

9/10

Add them back together

54 9/10

4 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
X(5)+2=244<br>help pls<br>(^_^)​
arsen [322]

Simplify both sides of the equation

  • 5x+2=244

Subtract 2 from both sides

  • 5x+2−2=244−2
  • 5x=242

Divide both sides by 5

\frac{5x}{5}  =  \frac{242}{5}

  • Answer

\: x =  \dfrac{242}{5}

OR

\: x =  48.4

6 0
2 years ago
Read 2 more answers
in the product rule for exponents, what do you do to the coefficients? what do you do to the exponents?
docker41 [41]

Answer:

Do not multiply the coefficients and the exponents. Remember, using the Product Rule add the exponents when the bases are the same.

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
Read 2 more answers
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