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lesya [120]
3 years ago
9

The table below shows the typical hours worked by employees at a company. A salaried employee makes $67,000 per year. Hourly emp

loyees get paid $25 per hour, but get $37.50 per hour for each hour over 40 hours. Sun. Mon. Tues. Wed. Thurs. Fri. Sat. 0 10 8 8 7 6.5 4.5 Which of the payment options would you recommend to a new employee?
a. Either one. Hourly and salaried employees earn the same amount per week.
b. Hourly pay. Hourly employees make more per week than salaried employees. c. Salaried pay. Salaried employees make more per week than hourly employees.
d. There is not enough information given to compare weekly earnings
Mathematics
2 answers:
nadezda [96]3 years ago
7 0
First, we must calculate the weekly pay of an employee that is paid a fixed amount. Given that there are 52 weeks in a year, the weekly pay for a regularly paid employee is: 67,000 / 52 = $1,288.46 Now, we calculate the number of hours an employee that is paid hourly works per week: 0 + 10 + 8 + 8 + 7 + 6.5 + 4.5 = 44 So this employee is paid: 25 x 40 + 37.5 x 4 = $1,150 Therefore, it is recommended that a new employee goes for the salaried pay since the weekly earnings are greater in this option. The answer is C<span>.</span>
posledela3 years ago
7 0
The answer is C. Salaries pay. Salaried employees make more per week than hourly employees.
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What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
Find the product. (y^3)^2 * y^7
Natasha_Volkova [10]
Firstly, let's take first factor:
(y^3)^2 = y^(3*2) = y^6
and then:
y^6 * y^7 = y^(6 + 7) = y^13

8 0
3 years ago
The table, the equation, and the graph show the rates at which three different students read in words per
Semmy [17]
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3 0
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Berto invested in a precious mineral. The value of the mineral tend to increase by about 11% per year. He invest $40,000 in 2015
stealth61 [152]

the difference from 40000 to the future value in 2020, namely 5 years later is simply the yield or interest amount.


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$40000\\ r=rate\to 11\%\to \frac{11}{100}\dotfill &0.11\\ t=years\dotfill &5 \end{cases} \\\\\\ I=(40000)(0.11)(5)\implies I=22000

5 0
3 years ago
Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco
chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

f(t) = \frac{1}{3}t^3-\frac{5}{2}t^2 + 80

f'(t) = t^2-5t

Substitute f'(t)=0.

t^2-5t=0

t(t-5)=0

t=0\ or\ t=5

It is given that  (0 ≤ t ≤ 10)

The test interval are (0,5) and (5,10)

For (0 < t < 5) the value of f'(t)

For (5 < t < 10) the value of f'(t) >0

Hence, the function is increasing from (5,10).

t = 0 corresponds to 2004.

Therefore, after 2009 the quality of the forests in this country improving.

7 0
3 years ago
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