Question

A 100 foot rope weighs 200 pounds. It is hanging vertically from the top of a tall building. After "x" feet have already been lifted, how much does the remainder of the rope (the hanging part) weigh? O2 pounds 200 pounds O2(100 – 2 pounds

Answer 1

Answer:

2*(100-X)

Step-by-step explanation:

Total length = 100 ft

Total weight =200 pounds

Assuming that the rope has an uniformly distributed weight, its weight per feet is:

$W_f = \frac{200}{100} =2\ lbs/ft$

If "x" feet have already been lifted, the length left to be lifted is 100 - x.

Therefore, the weight of the remainder of the rope is:

$W=2*(100-X)$