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Ulleksa [173]
3 years ago
15

A 100 foot rope weighs 200 pounds. It is hanging vertically from the top of a tall building. After "x" feet have already been li

fted, how much does the remainder of the rope (the hanging part) weigh? O2 pounds 200 pounds O2(100 – 2 pounds
Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer:

2*(100-X)

Step-by-step explanation:

Total length = 100 ft

Total weight =200 pounds

Assuming that the rope has an uniformly distributed weight, its weight per feet is:

W_f = \frac{200}{100} =2\ lbs/ft

If "x" feet have already been lifted, the length left to be lifted is 100 - x.

Therefore, the weight of the remainder of the rope is:

W=2*(100-X)

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