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chubhunter [2.5K]
4 years ago
12

The hexagon can be divided into six congruent and how many triangles?

Mathematics
1 answer:
maria [59]4 years ago
4 0
Six is the answer because a hexagon has 6 similar sides.
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What is the circumference of a circle that has a radius of 17 cm
Effectus [21]

Answer:

106.8

Step-by-step explanation:

17 * 2 = 34

34 * pi = 106.8

6 0
4 years ago
A hot air balloon is flying at and altitude of 2101 feet. If the angle of depression from the pilot in the balloon to a house on
alekssr [168]
The problem is modelled as right angle triangle, shown in the diagram below

The distance between the pilot and the house is labelled as x

Using the trigonometry ratio of sine
sin(31)= \frac{opposite}{hypotenuse}
sin(31)= \frac{2010}{x}
x= \frac{2101}{sin(31)} = 4079.3 ft

3 0
3 years ago
According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
3 years ago
Can someone please help me with this
marta [7]
N=4.5 In the picture are the steps you should follow to solve for n.

7 0
3 years ago
Which of the following is a unit for area?<br> ◦ m 3<br> ◦ inches<br> ◦ feet<br> ◦ cm 2
statuscvo [17]

Answer:

\huge\boxed{Answer\hookleftarrow}

<h3>✏ <u>cm²</u></h3>

⋆┈┈。゚❃ུ۪❀ུ۪❁ུ۪❃ུ۪❀゚ུ۪。┈┈⋆

6 0
3 years ago
Read 2 more answers
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