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3 years ago

The hexagon can be divided into six congruent and how many triangles?

Mathematics

1 answer:

maria [59]3 years ago

4 0

Six is the answer because a hexagon has 6 similar sides.

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AB = 4x

KiRa [710]

Answer:

AB=4×

DC=×+9

AD=6

BC=2y

Quadrilateral ABCD is a parallelogram if both pairs of Opposite sides are congruent. show that quadrilateral ABCD is a parallelogram by finding the Lengths of the Opposite side part

c 12,6

3 0

3 years ago

Write the equation of an ellipse with center (-2,-3), vertical major axis of length 14, and minor axis of

Tems11 [23]

Step-by-step explanation:

Since we have a vertical major axis, our ellipse is vertical.

The equation of a vertical ellipse is

$\frac{(y - k) {}^{2} }{ {a}^{2} } + \frac{(x - h) {}^{2} }{ {b}^{2} } = 1$

where

(h,k) is the center

a is the semi major axis,

b is the semi minor axis

First, let plug in our center

$\frac{(y + 3) {}^{2} }{ {a}^{2} } + \frac{(x + 2) {}^{2} }{ {b}^{2} } = 1$

Semi means half, so

a is half of 14 which is 7

B is half of 8, which is 4.

$\frac{(y + 3) {}^{2} }{49} + \frac{(x + 2) {}^{2} }{16} = 1$

5 0

1 year ago

Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc

Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

4 0

3 years ago

Read 2 more answers

Solve the equation for Y<br> 2x + y = -9

Westkost [7]

Alright, so first we'll have to get y on the other side

2x+y=-9

-y -y

+9 +9

2x+9=-y

Then divide is all by -1 so y is positive

-2x-9=y

5 0

3 years ago

Read 2 more answers

Consider the polynomial 8x^3+2x^2-20x-5 factor

pantera1 [17]

Answer:

(4x + 1)(2x² - 5)

Step-by-step explanation:

Given

8x³ + 2x² - 20x - 5 ( factor the first/second and third/fourth terms )

= 2x²(4x + 1) - 5(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(2x² - 5)

4 0

2 years ago