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Art [367]
3 years ago
8

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

B: If (50)x = 1, what are the possible values of x? Explain your answer. (5 points)
Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
The blue line is the graph of y=-4x + 5. Use the
WARRIOR [948]

Answer:

(1,1)

Step-by-step explanation:

1=-2(1)+3

1= -2 +3

1=1

1=-4(1)=5

1=-4=5

1=1

7 0
3 years ago
Read 2 more answers
Using the figure below, select the pairs of complementary angles.
Mila [183]

Answer:

c) <DBE and <EBC

Step-by-step explanation:

This is because when added together, both angles equal 90 degrees.

Complementary angles always equal 90 degrees.

8 0
3 years ago
Show your work plz.
iVinArrow [24]
C bc the x is where the right angle is and the 2 sides of a right angle is going to be equal
4 0
3 years ago
HELP URGENT I WILL GIVE 20 POINTS
Lunna [17]

h = 9.2 cm

Solution:

Base of smaller triangle = 5 cm

Height of smaller triangle = 2.3 cm

Base of larger triangle = 15 cm + 5 cm = 20 cm

Height of larger triangle = h

$\frac{2.3}{5}=\frac{h}{15+5}

$\frac{2.3}{5}=\frac{h}{20}

Multiply by 20 on both sides.

$20 \times \frac{2.3}{5}=\frac{h}{20} \times 20

$\frac{46}{5}=h

9.2 = h

So that Ryan should have add 15 and 5 to get a denominator of 20 on the right sides of the first line. Doing so gives the correct value, h = 9.2 cm.

8 0
3 years ago
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