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elena-14-01-66 [18.8K]
3 years ago
8

Is the graph increasing decreasing or constant?

Mathematics
2 answers:
cricket20 [7]3 years ago
6 0
It is going down negative as it is going the wrong way
KiRa [710]3 years ago
4 0

the graph is decreasing

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Plz help.....................
Nata [24]
I'm pretty positive it would be the second one from the top
7 0
3 years ago
For the line segment whose endpoints are R(1, 2) and S(6, 7), find the y value for the point located 3 ov`er 4 the distance from
Mrac [35]

Answer:

23/4

Step-by-step explanation:

This means that it is 3/4 of the distance in the x <u>and</u> y coordinates, so it is 3/4 of the way from 2 to 7, and since this is a difference of 7-2=5, then it is 2 + (5 * 3/4) or 2 + 15/4 or 23/4.

7 0
4 years ago
Using pythagoras theorem.
Nat2105 [25]
My friend... My method wasn't wrong and I couldn't find any mistake on my procedure... Check it out and analyze it by yourself... 
Download docx
3 0
3 years ago
Read 2 more answers
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
The mass of earth is 5.9 x 10^24. The mass of Pluto is 13,000,000,000,000,000,000,000 kg. Compared to Pluto, how much greater is
nadya68 [22]
5.9 × 10^24 = 5,900,000,000,000,000,000,000,000 minus
13,000,000,000,000,000,000,000 equals
5,887,000,000,000,000,000,000,000 kg
which is the amount greater that Earth's mass is. you could write this problem as
5.9 × 10^24 - 13 × 10^21 = 5.887 × 10^21
7 0
4 years ago
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