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elena-14-01-66 [18.8K]
3 years ago
8

Is the graph increasing decreasing or constant?

Mathematics
2 answers:
cricket20 [7]3 years ago
6 0
It is going down negative as it is going the wrong way
KiRa [710]3 years ago
4 0

the graph is decreasing

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Do y’all know the answer to this math question?
valkas [14]

9514 1404 393

Answer:

  BC = 35

Step-by-step explanation:

The sum of the segments is the overall length.

  AB +BC = AC

  (2x +6) + (6x +5) = 51 . . . . substitute given values

  8x +11 = 51 . . . . . . . . . . . . . collect terms

  8x = 40 . . . . . . . subtract 11

  x = 5 . . . . . . . . . divide by 8

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  BC = 35

5 0
3 years ago
Express 0.00562 in standard form​
saul85 [17]

Answer:

0.005+0.0006+0.00002=0.00562

Step-by-step explanation:

I think its how you do it

7 0
3 years ago
Please help me with this
Drupady [299]
The answer is d   9,891


3 0
3 years ago
A winery has a vat with two pipes leading to it. The inlet pipe can fill the vat in 5 ​hours, while the outlet pipe can empty it
Rashid [163]

Answer:

                 time=40/3hours\approx 13.3hours

Step-by-step explanation:

The rates are additive: you can calculate the<em> inlet </em>rate and the <em>outlet</em> rate and add them algebraically, i.e. the inlet rate will be positive and the outlet rate will be negative.

<u>1. Inlet rate:</u>

1vat/5hours

<u />

<u>2. Outlet rate:</u>

1vat/8hours

<u>3. Net rate:</u>

            \text{Inlet rate - outlet rate}=1vat/5hours-1vat/8hours\\\\ \text{Net rate}=(8-5)vat/40hour=3vat/40hour=(3/40)vat/hour

<u>4. Time to fill the vat</u>

           rate=amount/time\implies time=amount/rate\\ \\ time=1vat/(3vat/40hour)

          time=40/3hours\approx 13.3hours

7 0
3 years ago
Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
3 years ago
Read 2 more answers
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