4x+2y=-8 3x-2y=22x=y=

Mathematics

1 answer:

BaLLatris [955]4 years ago

3 0

This should be the answer and I showed you how to do it

(X,Y), ( 2,-8)

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7/3 + 3 * 2/3 - 1/3 squared

Fittoniya [83]

the answer is 3.6

I hope this helps

8 0

3 years ago

A radio station has a broadcast area in the shape of a circle with equation x^2 + y^2 = 5, 625, where the constant represents sq

sergij07 [2.7K]

SOLUTION:

Given: Equation of a circle describing a radio station broadcast area.

$\begin{gathered} x^2+y^2=5625 \\ \text{Comparing with the general equation of a circle:} \\ (x-a)^2+(y-b)^2=r^2 \\ \text{Where (a,b) represents the centre of the circle} \\ r\text{ represents the radius of the circle} \\ \text{Therefore,} \\ The\text{ centre is the origin (0,0)} \\ \text{radius,} \\ r^2=\text{ 5625} \\ \text{Square}-\text{root both sides} \\ \sqrt[]{r^2}=\text{ }\sqrt[]{5625} \\ r=\text{ 75 miles} \end{gathered}$

To find:

A) Intercepts; x-intercept, y-intercept

$\begin{gathered} x-\text{intercept} \\ \text{the value of x when y=0} \\ x^2_{}+y^2=5625 \\ x^2=5625 \\ \text{square}-\text{root both sides} \\ \sqrt[]{x^2}=\text{ }\sqrt[]{5625} \\ x=\text{ 75 miles} \end{gathered}$ $\begin{gathered} y-\text{intercept} \\ \text{the value of y when x=0} \\ x^2_{}+y^2=5625 \\ y^2=5625 \\ \text{square}-\text{root both sides} \\ \sqrt[]{y^2}=\text{ }\sqrt[]{5625} \\ y=\text{ 75 miles} \end{gathered}$

B) radius

$\begin{gathered} r^2=\text{ 5625} \\ \text{Square}-\text{root both sides} \\ \sqrt[]{r^2}=\text{ }\sqrt[]{5625} \\ r=\text{ 75 miles} \end{gathered}$

C) Area of region

The formula for area of a circle is given as:

$\begin{gathered} A=\text{ }\pi\times r^2 \\ A=\text{ }\frac{22}{7}\times75^2 \\ A=\frac{22}{7}\times5625 \\ A=\text{ 17678.57 sq miles (2 d.p)} \end{gathered}$

7 0

1 year ago

BRAINLIEST ANSWER PLEASE HELP ON A TIMER

ExtremeBDS [4]

Answer:

The answer is C i.e the probability is $\frac{4}{7}.\frac{3}{6}$

Step-by-step explanation:

Given 3 yellow tennis and 4 green tennis balls.

Now, Gordy will select one tennis balls which is green then the probablility of drawing one green tennis ball is

P(green tennis ball) = $\frac{4}{7}$

Now another ball is chosen randomly without replacing that first ball which is also green therefore the events are dependent. Hence, conditional probability

P(green on second pick given green on first pick) = $\frac{3}{6}$