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timurjin [86]
3 years ago
15

4x+2y=-8 3x-2y=22x=y=​

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0

This should be the answer and I showed you how to do it

(X,Y), ( 2,-8)

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Please help I need help
Andre45 [30]

An inverse variation can be represented by the equation

xy=k\to y=\dfrac{k}{x}

We have

\dfrac{y}{6}=x\qquad|\cdot6\\\\y=6x

Answer: The relationship does not show an inverse variation.

6 0
3 years ago
Find the coordinates of the midpoint M of ST. Then find the distance between points S and T. Round the distance to the nearest
ololo11 [35]

Answer:

Step-by-step explanation:

M is the midpoint

=>\left \{ {{x=\frac{6+7}{2} } \atop {y=\frac{-3-2}{2} }} \right

⇔\left \{ {x=\frac{13}{2} } \atop {y=\frac{-5}{2}}} \right.

⇒M(\frac{13}{2};\frac{-5}{2})

ST=\sqrt{(7-6) ^{2} +(-2+3)^{2}=\sqrt{2}=1.414

8 0
2 years ago
Number two anyone..?
sergey [27]

The equivalent expression is option A) 12(l+2a)

<u>Step-by-step explanation</u>:

  • The expression for total cost = 12l+24a
  • Taking 12 as common from all the terms in the expression,

we get, 12 (l+2a)

Therefore, The equivalent expression of 12l+24a is 12(l+2a).

3 0
3 years ago
An 18 m tall tree is broken during a severe storm. The distance from the base of the trunk to the point where the tip touches th
-BARSIC- [3]
I hope this helps you

6 0
3 years ago
The amount of saturated fat in a daily serving of a particular brand of breakfast cereal is normally distributed with mean 25 g
Soloha48 [4]

Answer:

a) \bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)

b) z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739

And using the normal standard distribution table and the complement rule we got:

P(z>2.739) =1- P(z

Step-by-step explanation:

From the info given if we define the random variable X as "amount of saturated fat in a daily serving of a particular brand of breakfast cereal " we know that the distribution of X is given by:

X \sim N(\mu =25, \sigma =4)

Part a

For this case the sample size would be n =30 and then the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)

Part b

We want to find this probability:

P(\bar X >27)

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739

And using the normal standard distribution table and the complement rule we got:

P(z>2.739) =1- P(z

3 0
3 years ago
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