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3 years ago

12

Find f(x) = 12/4x+2 find f(-1)

1 answer:

NeTakaya3 years ago

3 0

X=-1
12/-4=-3
-3+2=-1
The correct answer is -1

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A solid has faces that consist of 5 congruent squares and 4 congruent equilateral triangles. The solid has 9 vertices. How many

zimovet [89]

The answer is <span>A. 16 edges

For most of the solid shapes, we can use Euler's polyhedron formula:
f + v - e = 2
f - the number of faces
v - the number of vertices
e - the number of edges

We know:
f = 5 + 4 = 9
v = 9
e = ?

So:
</span>f + v - e = 2
9 + 9 - e = 2
18 - e = 2
18 = e + 2
e = 18 - 2
e = 16

8 0

3 years ago

Pie

$\textit{height of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2} ~~ \begin{cases} s=sides\\[-0.5em] \hrulefill\\ s=2 \end{cases}\implies h=\cfrac{2\sqrt{3}}{2}\implies h=\sqrt{3}\implies h\approx 1.7$

5 0

1 year ago

A card player selects 2 cards from a deck of 52 cards at random without replacement. The deck contains 4 aces.

Nataliya [291]

Answer:

2/52

Step-by-step explanation:

If he took one ace out of 52 cards then it would have been 4/52

but as he's taking 2 aces out of 52 cards it is 2/52

8 0

3 years ago

Read 2 more answers

Israel added $120 to his savings. This added amount represents 1/6 of his total savings. If s represents the total savings, whic

oee [108]

Calculista Ambitious

the correct question in the attached figure

Let

s----------> total savings

case a) Israel added $80 to his savings

we know that

80=(1/8)*s-------> multiply by 8 both sides------> s=$640

the answer case a) is

the equation is

80=(1/8)*s

case b) Israel added $120 to his savings

we know that

120=(1/8)*s-------> multiply by 8 both sides------> s=$960

the answer case b) is

the equation is

120=(1/8)*s

Read more on Brainly.com - brainly.com/question/10503464#readmore

7 0

4 years ago

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago