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3 years ago

Find f(x) = 12/4x+2 find f(-1)

Mathematics

1 answer:

NeTakaya3 years ago

3 0

X=-1
12/-4=-3
-3+2=-1
The correct answer is -1

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Help pls, how do i answer this one

nasty-shy [4]

Answer:

h > 24

Step-by-step explanation:

h/3 > 8

so basially you move the number three from the left side to the right side

so from division to multiplication

h > 8 x 3
h > 24
Solved !

Hope it helped ! Have a nice day !

5 0

2 years ago

Which expression is equivalent to this expression?<br><br> 3/4 (4h – 6)

sergij07 [2.7K]

Answer:
3h-9/2
Step-by-step explanation:
3/4(4h-6)=3h-18/4
simplify
3h-9/2

7 0

3 years ago

Find all polar coordinates of point P = (6, 31°). Im really struggling with this problem and I can't seem to find a consistent a

Kaylis [27]

Answer:

1. (6, -329°) (-6, 211°) (-6, -149°)

2. (5, -5π/3) (-5, 4π/3) (-5,-2π/3)

Notice: (+,+),(+,-),(-,+),(-,-).

If we consider angles beyond 360° or 2π, many other names for these points can be determined.

The polar coordinate can be written as (r, θ) = (r, θ + 2nπ) or (r, θ) = [ - r, θ + (2n + 1)π ], where n is any integer

3 0

3 years ago

Read 2 more answers

Which represents the reflection of f(x)=√x over the y-axis?

ololo11 [35]

We are looking for the graph of $y=\sqrt{-x}$ . which is shown in the attached image.

8 0

2 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

3 years ago