4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.
Start with
Taken mod 4, the last two terms vanish and we're left with
We have 
, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.
Taken mod 7, the first and last terms vanish and we're left with
which is what we want, so no adjustments needed here.
Taken mod 9, the first two terms vanish and we're left with
so we don't need to make any adjustments here, and we end up with 
.
By the Chinese remainder theorem, we find that any 
such that
is a solution to this system, i.e. 
for any integer 
, the smallest and positive of which is 149.
Answer:
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
2/4 =1/2 or 50%.
Answer: Length 1,132 ft
Step-by-step explanation: Im not sure if this is the one your talking about but here.
Answer:
1 /1 ; 360°
Step-by-step explanation:
Start time = 2:30 pm
Stop time = 3:30 pm
Minute hand makes a complete revolution per hour ;
This means that the minutes hand revolves round the whole circle in one hour, hence fraction of the circle covered by the minute hand between 2:30 pm - 3:30 pm is 1/1 = 1
The angle turned by the minutes hand :
1 complete revolution = 360°
A circle covers 360°
1 /1 fraction of a circle = 1/1 * 360° = 360°
Hence, angle turned by the minute hand = 360°
