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frosja888 [35]
3 years ago
9

Find the distance of (2,5) and (-1,3)

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

Answer:

\sqrt{13}

Step-by-step explanation:

Use the distance formula:

\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Insert the values:

(2_{x1},5_{y1})\\\\(-1_{x1},3_{y2})\\\\\\sqrt{(-1-2)^2+(3-5)^2}

Simplify:

\sqrt{(-1-2)^2+(3-5)^2}\\\\ \sqrt{(-3)^2+(-2)^2}\\\\ \sqrt{9+4}\\\\\sqrt{13}

The distance between the two points is the square root of 13.

:Done

irinina [24]3 years ago
6 0

Answer: \sqrt{13} or 3.61

Step-by-step explanation:

\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

\sqrt{\left(-1-2\right)^2+\left(3-5\right)^2}

\sqrt{9+4}

=\sqrt{13}

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Solve 13 - 2x &gt; 21<br>x&gt;-4<br>x &gt; -17<br>x&lt; -17<br>x&lt;-4​
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