(4.61×10^4)-(2.75×10^4)

(Help please) A transformation was performed on oval A as shown in the graph. What type of transformation was performed? Does th

labwork [276]

Answer: B. Translation, yes

-A is incorrect because the shape did not change
-C is incorrect because the shape isn’t reflected over the y axis
-D is incorrect because it’s clearly moved to a completely different part of the grid

3 0

3 years ago

Read 2 more answers

The difference of two numbers is 90 and their quotient is 10

bija089 [108]

To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) Difference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10

Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

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Answer: The numbers are 100 and 10

3 0

3 years ago

Alexandra saved up her money and bought a

Mars2501 [29]

Answer: .375

Step-by-step explanation:

Instead of doing 8/3 it would be 3/8 since there are 8 cars being put inside of 3 feet. Therefore, 3/8= .375

7 0

3 years ago

Please help me solve this!!

Brut [27]

Answer:

30

by-step explanation:

5*5=30

3 0

3 years ago

A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i

Ray Of Light [21]

Answer:

Step-by-step explanation:

Given: A line m is perpendicular to the angle bisector of ∠A. We call this

intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

To Prove: ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are

equal.

Solution: Now, In ΔADM and ΔADN

∠MAD=∠NAD ...(1) (∵Given)

AD=AD ...(2) (∵common side)

∠ADM=∠ADN ...(3) (∵Given)

Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN

( ∵ ASA congruence rule)

⇒ AM=AN

Now, In Δ AMN

AM=AN (∵ Proved)

Hence, ΔAMN is an isosceles triangle.

7 0

3 years ago