we are given 

we have to find theta 
so, firstly we can write sin in terms of cos

now, we can set it equal 

Since, both sides are cos 
so, we can set angles equal 

now, we can solve for theta
we get 
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First, some housekeeping:
cos = 12/13 is incomplete; "cos" must have an argument (input).
cos x = 12/13 is fine; here "cos" has the argument (input) x.
Given that cos x = 12/13, find sin x.  To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.
12^2 + opp^2 = 13^2, or            opp^2 = 169-144 = 25.
Then the opp side could be either 5 or -5.  Let's assume that it's +5, and that angle x is in the first quadrant.
Then sin x = opp / hyp  =  5/13   (answer)
cos 2 is an entirely different kind of problem.  Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).
Using a calculator:  cos 2 = -0.416.  Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.
        
             
        
        
        
Answer:
e and f is 1.34
Step-by-step explanation:
 
        
                    
             
        
        
        
y = 55/10x + 50 is the equation to represent this situation
 
        
             
        
        
        
Answer:
k is the option that makes sense