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Elden [556K]
3 years ago
9

April had 3 7 of a pound of pecans. her sister ate 2 3 of april's pecans. how many pounds of pecans did april's sister eat?

Mathematics
2 answers:
RideAnS [48]3 years ago
7 0
 <span>April had </span><span>3/7</span><span> of a pound of pecans. Her sister ate </span><span>2/3</span><span> of April's pecans. How many pounds of pecans did April's sister eat?

Answer:2/7

Explaining </span><span>3/7</span><span> x </span><span>2/3</span><span> = </span><span>621</span><span> = </span><span>2/7
                                                             Good Luck! :)



</span>
vodka [1.7K]3 years ago
4 0

Answer: The right answer is 2/7

Step-by-step explanation: I just answered the usatestprep question please mark me branlyist I need to level up

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Answer:

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Step-by-step explanation:

(p+\frac{7}{3})(\frac{6}{p})

Making denominator same in first bracket we get

(\frac{3p+7}{3})(\frac{6}{p})

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Dividing 6 by 3 we get 2

(\frac{(3p+7)*2}{p})

using distributive law

(\frac{6p+14}{p})\\

Hence this is our answer

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A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
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FromTheMoon [43]

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Step-by-step explanation:

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andriy [413]

The required picture is attached below :

Answer:

1 /32 yard³

Step-by-step explanation:

The volume of box can be obtained using the relation :

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