Question

The ratio of money in Brian's wallet to Colin's wallet one day was 7:2. Brian spent ?39 that day. Brian now had ?4 less than Colin. How much did Colin initially have?

Answer 1

Answer:

$17.2

Step-by-step explanation:

The ratio of money in Brian's wallet to Colin's wallet is;

$B:C=7:2$

$\implies \frac{B}{C}=\frac{7}{2}$

$\implies B=\frac{7C}{2}$ .....(1)

If Brian spent $39, then he now

has: $(B-39)

This amount compared to Collin's money is

$(B-39)=C+4

B=C+4+39

B=C+43.....(2)

Put equation (1) in (2)

$\frac{7C}{2}=C+43$

$7C=2C+86$

$7C-2C=86$

$5C=86$

$C=17.2$

Collins initially had $17.2