What is the solution to the system of equations below? 3x+4y-2z=-1 -x+6y+2z=7 4x-2y+3z=27
1 answer:
Answer:
(3x+4y-2z=-1)= x=-1/3-4/3y+2/3z
(-x+6y=2z)= x=-7+6y=2z
(4x-2y+3z=27)= x=27/4+1/2-3/4z
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