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DiKsa [7]
3 years ago
9

What is the solution to the system of equations below? 3x+4y-2z=-1 -x+6y+2z=7 4x-2y+3z=27

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

(3x+4y-2z=-1)= x=-1/3-4/3y+2/3z

(-x+6y=2z)= x=-7+6y=2z

(4x-2y+3z=27)= x=27/4+1/2-3/4z

Step-by-step explanation:

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Answers:

4;  20;  3x² - 4x + 3; 52;  17

Step-by-step explanation:

f(-1):  replace x in f(x) = x² + 3 with -1:  f(-1)  =  (-1)² + 3 = 4

f(-4) + g(-1) = (-4)² + 3 + <em>2(-1) + 3</em>  =  16 + 3 <em>- 2 + 3</em> = 20   <em>(since g(x) = 2X + 3)</em>

<em />

3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6  =  3x² - 4x + 3

f(g(2)):  First, evaluate g(2).  It is g(2) = 2(2) + 3 = 7.  Next, use this output, 7, as the input to f(x):    f(g(x)) = (7)² + 3 = 49 + 3 = 52

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8 0
3 years ago
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