The answer is 1040EZ. That is the shortest and simplest tax form.
Answer:
B. style=text-align: right
Explanation:
text-align is a CSS property having 5 types of values. Each of values define below.
left - Aligns content to left.
right - Aligns content to right.
center - Centers the content.
justify - Depends on the width of the content, it will align itself to both left and righ
inherit - It specifies the the value of text-align should be taken from parent element.
Please provide the language you're using when you ask for programming help, otherwise you aren't going to get the answer that you are looking for.
Here it is in Java, and I'm assuming the number is given via user input? Otherwise, just remove the user input function and replace the integer with a value of your choice. Note, that this isn't the full code; only what is relevant to the question.
public static void main(String[] args) {
int num = numInput(10);
printDoubles(num, 100); // You can create a user input function for
// maxValue if you wanted to.
}
/**
* Receives user input between 0 and the absolute value of maxInput.
* @param maxInput The largest absolute value that can be input.
*/
private static int numInput(int maxInput) {
Scanner sc = new Scanner(System.in);
maxInput = Math.abs(maxInput);
int num = 0;
while (!(num > 0 && num <= maxInput)) {
num = sc.nextInt();
if (!(num > 0 && num <= maxInput)) {
System.out.println("Input too small or too large");
}
}
return num;
}
/**
* Continues to print out num doubled until maxValue is reached.
* @param num The number to be printed.
* @param maxValue The maximum value (not including in which num can be doubled to.
*/
private static void printDoubles(int num, int maxValue) {
if (num >= maxValue) {
System.out.println("No output.");
}
while (true) {
if (num >= maxValue) {
break;
}
if (num < maxValue) {
System.out.print(num + " ");
}
num *= 2;
}
System.out.println();
}