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zzz [600]
3 years ago
10

Plz HELP! ASAP for both 9 and 10 plz

Mathematics
2 answers:
ale4655 [162]3 years ago
8 0

Answer:

domain: 0 - 10 range: 0 - 32

Step-by-step explanation:

Take the lowest x and the highest x and put them in set values to get domain.

lowest x = 0 and highest x = 10.

Take the lowest y and the highest y and put them in set values to get range.

lowest y = 0 and highest y = 32

saw5 [17]3 years ago
3 0

Answer:

9. Distance from the bay (in yards), i.e, 0, 5 and 10 are the domain of the graph.

10-0=10

10. height of the golf ball (in yards), i.e, 15,32 and 0 are the range og the graph.

32 - 0 = 32

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What is the answer to this question
Airida [17]

the answer would be 67,127 because the number in the ones would be 7 and the tens number would be 2 since it wouldn't more than 1.

67,102

67,135

     1-7

67,127

8 0
3 years ago
3x - 7 = 3x + 9; x =<br><br> Please can someone help me and show me the answers step by steps
anyanavicka [17]

Answer:

i think probably x∉∅

Step-by-step explanation:

3x-7 = 3x+9

-7 = 9

so x∉∅

5 0
2 years ago
Read 2 more answers
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
1 year ago
Sarah bought two t-shirts and one sweatshirt. The t-shirts cost $15.22 each. If Sarah spent a total of $67.94,how many dollars d
Lena [83]

Answer:

111

Step-by-step explanation:

6 0
3 years ago
Please help me I have been struggling
maxonik [38]

The answer is D. It can't be considered a funtion unless each X value only has 1 Y value corresponding to it. In this problem, you see the X value 3 paired with -1 and 1.

7 0
3 years ago
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