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Vaselesa [24]
3 years ago
7

What is G (f) = 3k (2) -22 k=4 I can't get it

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0
<span>Solution    k = {-1, -5}</span>
Inessa05 [86]3 years ago
5 0
G (f) is just a variable, and that's what confuses most people. if you wanted to, the equation could still be the same and be written as:

x = 3k (2) -22 ;k=4

But, to get the answer, you substitute k as 4, shown below:

x = 3(4) (2) -22

Next you multiply:

x = 12 (2) -22

Then multiply 12 by 2:

x = 24 -22

Then subtract and the answer will be 2

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frosja888 [35]
This is because 2÷3 = 0 . Six repeating but the Calculator rounds the last 6 to 7 because I can't fit all the repeating sixes in one calculator
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I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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2 years ago
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