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Semmy [17]
4 years ago
13

Is the reduced form of cytochrome c more likely to give up its electron to oxidized cytochrome a or cytochrome b, why? Provide a

brief rationale for your answer.
Biology
1 answer:
Vadim26 [7]4 years ago
3 0

Answer:

The reduced form of cytochrome c more likely to give up its electron to oxidized cytochrome a having a higher reduction potential.  

Explanation:

Electrons from NADH and FADH2 flow spontaneously from one electron carrier of the electron transport chain to the other. This occurs since the proteins of the ETC are present in the order of increasing reduction potential. The reduced cytochrome b has lower reduction potential than cytochrome c1 which in turn has a lower reduction potential than the cytochrome c.

Cytochrome c is a soluble protein and its single heme accepts an electron from cytochrome b of the Complex III. Now, cytochrome c moves to complex IV which has higher reduction potential and donates the electron to cytochrome a which in turn passes the electrons to O2 via cytochrome a3.

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Explanation:

Noble gases have a full outer energy level and are inactive. These atoms are considered inert.

Hope this helps

Good Luck

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3 years ago
Map One method for separating polypeptides makes use of their different solubilities. The solubility of large polypeptides in wa
PSYCHO15rus [73]

Answer: For (a):

(Lys-Ala)3 is soluble and (Gly)zo is not soluble.

(b) (Glu)zo is soluble and (Phe-Met) is not soluble.

(c) ( Asn-Ser-His) is soluble and (Ala- Asp-Gly) is not soluble.

(d) (Asn-Ser-His) is soluble and (Ala-Ser-Gly).

Explanation:Firstly, the solubility of polypeptides relies on polar groups in the R group of the side chain and also ionized groups because these groups can interact with dipole bond of water.

For (a): (Gly)zo, no R group of the side chain of (Gly)zo is polar nor ionizable and solubility is based on the ability of R group of polypeptides to be polar or ionized while in polypeptides of (Lys-Ala), Lys is polar and therefore soluble though Ala in the compound is not polar nor ionizable but the presence of Lys makes the polypeptide to be soluble.

(b) (Glu)zo is a polar peptide, therefore soluble peptides while both the combination of (Phe-Met)3 gives polypeptides that are not polar therefore not soluble.

(c) In poypeptide of (Ala-Asp-Gly)s, the R group on the side chain of both Ala and Gly are neither polar nor ionizable therefore cannot be soluble even though Asp( which at PH 3 can partially be protonated and partially deprotonated to make it soluble) is present in the polypeptide. Therefore the polypeptide of Ala-Asp-Gly is not soluble compared to Asn- Ser-His, where Asn has polar covalent bond which can interact with water, His which at pH 6 will be half protonated and half deprotonated making the substance to react with water and also Ser is a soluble polypeptide too.

(d) Also between (Ala- Ser-Gly) and ( Asn- Ser-His), polypeptide with (Asn-Ser-His) will be considered soluble because Ala and Gly have R groups that neither polar nor ionizable though Ser is soluble but common to both substances, its influence will not be effective and (His) is a soluble which at pH 6 get partially protonated and deprotonated.

3 0
3 years ago
Characteristics nucleus cell wall Kingdom A absent (prokaryote) present autotrophs or heterotrophs Kingdom B present (eukaryote)
Korolek [52]

Answer:

It's the last answer choice

Explanation:

You basically look at the chart and see if the answer choices match.

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