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Trava [24]
3 years ago
15

Find the derivative of f(x)= sqrt(12-x^6)

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

-3x^5 /√(12 - x^6).

Step-by-step explanation:

f(x)= sqrt(12-x^6)

f(x) = ( 12 - x^6)^1/2

Using the Chain Rule:

f'(x) = 1/2(12 - x^6)^-1/2 * -6x^5

=  -6x^5 /  2(12 - x^6) ^ 1/2

= -6x^5 /2√(12 - x^6)

= -3x^5 /√(12 - x^6).

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The augmented matrix of a consistent system of five equa- tions in seven unknowns has rank equal to three. How many parameters a
ale4655 [162]

Answer:

4 parameters are necessary to specify all solutions and correspond to the number of free variables of the system.

Step-by-step explanation:

Remember that the number of free variables of a system is equal to m-rank(A) where m is the number of unknowns variables and A is the matrix of the system.

Since the system is consistent and the rank of the matrix is 3 then echelon form of the augmented matrix has two rows of zeros.

Then m-rank(A)=7-3=4.

6 0
3 years ago
The​ point-slope form of the equation of a nonvertical line with slope, m, that passes through the point (x1,y1) is...?
natulia [17]

Answer:

  b. y-y1 = m(x-x1)

Step-by-step explanation:

It's a matter of definition. There are perhaps a dozen useful forms of equations for a line. Each has its own name (and use). Here are some of them.

  • slope-intercept form: y = mx + b
  • point-slope form: y -y1 = m(x -x1)
  • two-point form: y = (y2-y1)/(x2-x1)(x -x1) +y1
  • intercept form: x/a +y/b = 1
  • standard form: ax +by = c
  • general form: ax +by +c = 0

Adding y1 to the point-slope form puts it in an alternate form that is useful for getting to slope-intercept form faster: y = m(x -x1) +y1. I use this when asked to write the equation of a line with given slope through a point, with the result in slope-intercept form.

3 0
3 years ago
Yosef typed a 36 word paragraph in 2/3 minute. What is his typing speed, in words per minute?
Yakvenalex [24]

Answer:

the answer is:

Yousef typing speed, in words per minute is

equal to

54 words

minute

8 0
2 years ago
What is the square root of 50 rounded to the nearest hundredth?
tamaranim1 [39]
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
8 0
3 years ago
alex runs on the track at the school each weekday morning if he runs 5.9 miles each day about how much does he run every month
vovangra [49]
Since Alex runs on weekday mornings he most likely runs 118 miles a month.
3 0
3 years ago
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