Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
1. 15/3:3/3
2. 5:1
1. find the same denominator
2. divide by denominator
Answer:
1/8
Step-by-step explanation:
1/4 ÷ 2 = 0.125
0.125 as a decimal is 1/8
Step 1: Set up the proportion
4/12 = 10/x
Step 2: Cross multiply to get
120 = 4x
Step 3: Divide all by 4 to get
30 = x
Answer: So in total, 10 students would spend $30 on lunch!
Answer:
Claim is false
Step-by-step explanation:
Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.

n = 20
Since n <30
So we will use t test
Formula : 
s = standard deviation = 391
x = 3600
n = 20


Degree of freedom = n-1 = 20-1 = 19
α=0.10
So, using t table
= 1.72
t critical > t calculated
So we accept the null hypothesis
Hence we reject the claim that the mean credit card debt in a town is greater than $3500.