I will assume you mistyped this question. For y = -1/16x^2 + 4x + 3, the answers to this question are
a) 3 feet
b) 67 feet
c) 64.741 feet
For a) we note that at x = 0, that is the instant where the ball leaves the hand. y(0) = 0.
For b), we find the vertex of y = -1/16x^2 + 4x + 3
y = -1/16x^2 + 4x + 3
y = -1/16(x^2 - 64x) + 3
y = -1/16(x^2 - 64x + 1024 - 1024) + 3
y = -1/16((x-32)^2 - 1024) + 3
y = -1/16(x-32)^2 + 64 + 3
y = -1/16(x-32)^2 + 67
The vertex is at (32,67) so 67 is the maximum height.
For c), we find the x-intercepts with the quadratic formula on
y = -1/16x^2 + 4x + 3=0:
x = [ -b ± √b^2 - 4ac ] / (2a)<span>
x = [ -4 ± √4^2 - 4(-1/16)(3) ] / (2(-1/16))
x = -0.741, 64.741
Only the positive solution, so 64.741 feet </span>
1/8 + 1/4
the least common multiple of 8 and 4 is 8. Convert 1/8 and 1/4 to fractions with denominator 8.
1/8 + 2/8
Because 1/8 and 2/8 have the same denominator, add them by adding their numerators.
1+2/8
add 1 and 2 to get 3
3/8 or 0.375
Consecutive numbers are always 1 away from each other
3,4
so consecutive is represented by
x and x+1
so sum is -171
x+x+1=-171
add like terms
2x+1=-171
subtract 1 from both sides
2x=-172
divide both sides by 2
x=-86
subustitute
x+1=otehr number
x+1=-86+1=-85
answer is -85 and -86
Answer:
lal lesthan or equal to 5
Step-by-step explanation:
