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lara [203]
3 years ago
12

Hurrry i need help nowwwwwwwwwwwwwwwww

Mathematics
2 answers:
polet [3.4K]3 years ago
4 0
The answer is A
hope this helps ;)
nikklg [1K]3 years ago
3 0

Answer: A y=4x^2+1

Step-by-step explanation:According to slope A is the answer

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The system of equations relates the distance, y,
Monica [59]
Is it 7.1 or something I don’t know for sure
8 0
3 years ago
£3.50= %of£10 answer this question i raelly dont get it in any way
ziro4ka [17]
\dfrac{\pounds 3.50}{\pounds10}\cdot100\%=\\
0.35\cdot100\%=\\
35\%
3 0
3 years ago
The rectangular prism below has a total surface area of 198 in2. Use the net below to find the missing dimension, x.
inessss [21]
The missing dimension, x, is 7.5.

if you take 45 and divide it by 6 you can get the next dimension needed to get the full number, 45. You can also find it by dividing 35 and 4. I hope this helps.
4 0
3 years ago
This doesn’t make sense explain plz
AnnZ [28]

Its simple, graph them.

For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.

For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.

When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.

I hope this cleared up your confusion, brainliest/heart would help.

5 0
3 years ago
Which matrix represents the system of equations shown below? 2x-y=-6 and x-6y=13​
dezoksy [38]

Answer: D

<u>Step-by-step explanation:</u>

The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]

The product will result in the solution for the x- and y-values of the system.

6 0
4 years ago
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