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Sindrei [870]
2 years ago
7

A shoe company wants to test an updated model of a running shoe on its wear after one month of running. They recruit 50 people w

ho run on a regular basis to participate in the study. They will have the runners wear the shoes when they run for two months. After two months, the wear on the shoes will be determined using the depth of the tread and flexibility of the toe box. The wear between the new model and the original model will then be compared. The company decides to use a matched pairs design and devises two options.
Option A: The 50 subjects are paired based on running ability. The fastest two runners are paired together, the next fastest two, etc. For each pair of runners, the researcher will flip a coin. If the coin lands on heads, then the first runner will receive the new model of shoes and the second runner will receive the original model. If the coin lands on tails, the first runner will receive the original model of shoes and the second runner will receive the new model. After 2 months of use, the difference in wear for the pairs of runners will be determined.

Option B: The 50 subjects will each receive both models of shoes. At the beginning, the runner will flip a coin, and if it lands on heads, they will wear the new model on their right foot and the original model on their left foot. Then after one month, they will change and use the new model on their left foot and the original model on their right foot. After the second month, the wear for each model will be determined and compared for the 50 runners.

Which option should the shoe company use to compare the two models?

A: The runners are paired based on their running ability. This will provide an accurate comparison for the difference in wear between the original model and the new model.
B: Each runner varies with respect to multiple variables. Each runner should use both models to account for their individual differences. This will provide an accurate comparison for the difference in wear between the models.
Both A and B: Both provide an accurate comparison for the difference in wear between the original model and the new model. The runners are paired in option A based on running ability, and each runner uses both models in option B.
Neither A nor B: Neither provides an accurate comparison to determine the difference in wear for the two models. This experiment should be a randomized block design.
Mathematics
1 answer:
Arlecino [84]2 years ago
7 0

Answer:

B: Each runner varies with respect to multiple variables. Each runner should use both models to account for their individual differences. This will provide an accurate comparison for the difference in wear between the models.

Step-by-step explanation:

Since the shoe company wants to test the wear of the shoes after two months, it means that option B will be the most accurate.

This because everybody has peculiarities in the bodies and also running patterns. These could have an effect on either of their legs. Thus, having to wear a new one on one leg and the original one on another leg for a month and then replacing with the second leg of both for the other month would be the best way to know the true effect of wear on the shoes because they have both been subject to same conditions within exactly the same timeframe.

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4 3/4

Step-by-step explanation:

Just multiply 1 3/4 and 3 = 4 3/4

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What is the answer to this problem?
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The statement 'of ' represents multiplication.

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3 years ago
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What is the height of a rectangle<br> whose base is 40 inches and whose<br> diagonal is 41 inches?
romanna [79]

Answer:

You must draw a right triangle and label the hypotenuse as 41 and the longest leg (horizontal in this case, since we are to determine the height) as 40. We do not know the height so call it h.

Now the Pythagorean (sp /) Theorem states that the square of the hyp. is equal to the sum of the squares of the two legs.

so, 41 ^ 2 = 40 ^ 2 + h ^ 2

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Step-by-step explanation:

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3 years ago
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A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
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