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3 years ago

6 Σ (12 – 4 i) i = 3

Mathematics

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:

- 24

Step-by-step explanation:

We have to get the value of the following sum as given.

$\sum_{3}^{6} (12-4i)$

This can be written in language as the summation of (12 -4i) where value of i ranges from 3 to 6.

$\sum_{3}^{6} (12-4i)$

= [12 - 4(3)] + [12 - 4(4)] + [12 - 4(5)] + [12 - 4(6)]

= 0 + [- 4] + [- 8] + [- 12]

= - 24 (Answer)

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Find the distance between the two points rounding to the nearest tenth (if

zimovet [89]

Answer:

Step-by-step explanation:

=(−3−2)2+(−4−8)2

=(−5)2+(−12)2

=25+144

d=25+144

=√169

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6 0

3 years ago

What function is the inverse of y=-3x+6/7

Kisachek [45]

Y = -3x + 6/7
switch the x and y, then solve for y:
$y = -3x + \frac{6}{7} \\ x = - 3y + \frac{6}{7} \\ 3y = - x + \frac{6}{7} \:$
$3y \div 3 = (- x + \frac{6}{7}) \div 3 \\ y = - x \div 3 \: + \frac{2}{7}$
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4 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$