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dybincka [34]
4 years ago
15

Find the average rate of change of the function over the given interval.

Mathematics
1 answer:
Minchanka [31]4 years ago
6 0

Answer:

Average rate of change = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

Step-by-step explanation:

The average rate of change of the function

F(t) = 2t^2 - 1 ,  [ 5,5.1 ]

solution

\frac{f(5.1)-f(5)}{5.1 - 5} = \frac{2*(5.1)^2-1-(2*5^2-1)}{0.1}   = [ 2 ( 26.01 - 25 ) / 0.1 ]

= 2.02 / 0.1 = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

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<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

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